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55x=9x^2-324
We move all terms to the left:
55x-(9x^2-324)=0
We get rid of parentheses
-9x^2+55x+324=0
a = -9; b = 55; c = +324;
Δ = b2-4ac
Δ = 552-4·(-9)·324
Δ = 14689
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-\sqrt{14689}}{2*-9}=\frac{-55-\sqrt{14689}}{-18} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+\sqrt{14689}}{2*-9}=\frac{-55+\sqrt{14689}}{-18} $
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